What is the area of this figure? Drag and drop the appropriate number into the box. A = ft² A shape made up of a rectangle with a length of 18 feet, another rectangle attached to the first rectangle with a length of 5 feet and a height of 5 feet, another rectangle attached to the second rectangle with a length of 1 foot and a height of 4 feet. The longest straight edge of the shape is labeled with a height of 15 feet.

The area of the figure is 137 feet.

Step-by-step explanation:

1st rectangle,

length = 18 feet and height = x

2nd rectangle,

length = 5 feet and height = 5 feet.

3rd rectangle,

length = 1 foot and height = 4 feet.

Area of 1st rectangle = 186 = 108 feet

Area of 2nd rectangle = 55 = 25 feet

Area of 3rd rectangle = 14 = 4 feet

∴ Area of the figure = 108+25+4 = 137 feet.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

i believe it's a.

i'm not sure on this one, most likely correct.