Scores on the Common final exam in Stat 1222 course are randomly distributed with mean 75 and Standard deviation 5. The department decides to give A to all students whose scores are in the top 10% on this exam.
What is the minimum score for a student to receive A?

The minimum score for a student to receive A is 81.4.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The department decides to give A to all students whose scores are in the top 10% on this exam.

What is the minimum score for a student to receive A?

The minimum score is the value of X when Z has a pvalue of 1-0.1 = 0.9. So it is X when Z = 1.28.

The minimum score for a student to receive A is 81.4.

1gm = 1000mg so 0.1gm = 1000mg

first, convert the weight to kg

160lb * 1kg/2.2lb = 72.7kg

next, the dose

72.7kg * 100mg/kg = 7270mg

i will pick c put check it over to be sure

step-by-step explanation: