Given that the points (-1,5) and (2, 1) are vertices of a rectangle with sides parallel to the axes, how much longer is the length
than the width?
1 unit
2 units
3 units
4 units
E)
5 units

Option A - 1 Unit

Step-by-step explanation:

Step 1 :

Given the 2 vertices of the rectangle are (-1,5) and (2, 1) and the sides are parallel to the axes

Let A = (-1,5) and C = (2, 1)

Step 2 :

The x co- ordinate of A is -1 and y co-ordinate is 5

The x co- ordinate of A is 2 and y co-ordinate is 1

Let B and D be the other 2 vertices of the rectangle.

B is the intersection of the line drawn from A and the perpendicular drawn from the point C.  Side AB is parallel to the axis -x and side BC is parallel to  axis y

Hence the point B will have the x co-ordinate of the point A and the Y co ordinate of the point C which is (2,5) .

Similarly, D is the intersection of  line drawn from C and perpendicular drawn from  point A.  Side CD is parallel to the axis x and side AD is parallel to axis y

Hence the point D will have the x co-ordinate of the point C and the Y co ordinate of the point A which is (-1,1).

Step 3:

Hence the 4 vertices of the rectangle are

A (-1,5) B(2,5), C(2,1) and D(-1,1)

Length of side AB is 2-(-1) = 3 units

Length of side BC is  5 - 1 = 4 units.

Hence the rectangle's length will be 4 units and rectangle's width will be 3 units

So, the length is 1 unit longer than the width.

1,8,15,22,29,36,43,50

step-by-step explanation:

answer:

1.14285714286

step-by-step explanation:

divide 40 into 35 and you will get your answer