Does 131 appear in the sequence 6n-1

Step-by-step explanation:

6n - 1 = 131 ⇔ 6n = 132 ⇔ n = 132÷6 = 22

then 131 is the 22 term of the sequence

if you was gonna solve for a, a is a   < -12

for this case we must apply distributive property to the following expression:

the distributive property states that:

then, when applying the property we have to multiply the -2 for each term within the parenthesis: