Small solid glass ball of radius r is irradiated by a beam of positive ions and gains a charge + q distributed uniformly throughout its volume. What is the potential (relative to infinity) at location A, inside the ball, a distance r / 6 from the center of the ball? (Use any variable or symbol stated above along with the following as necessary: ε 0 .) Give the numerical coefficient in the form of a simple fraction

V=6q/20πεor= 3q/10πεor

Step-by-step explanation:

distance between the charges is r-r/6 since the charges are located at the surface and r/6. V=w/q and W =Force X distance =kQq/r

and V = Kq/r also k =1/4πεo. Hence the potential at location A inside the ball to the charge +q at the surface is 3q/10πεor

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2