For a hypothesis test of H0: p = 0.40 against the alternative Ha: p > 0.40, the z test statistic is found to be 2.25. What can be said about this find

Reject the null hypothesis because the test statistic 2.25 falls in the rejection region of the critical value.

Step by step explaination:

H0: p = 0.40

Ha: p > 0.40

Decision rule: Reject the null hypothesis (H0) if the test statistic is greater than the critical value.

Test statistic (z) = 2.25

The test is a one-tailed test because the alternate hypothesis is expressed using the inequality greater than

Assuming a 5% significance level, the critical value is 1.645

Conclusion: Reject H0 because the test statistic 2.25 is greater than the critical value 1.645.

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )