To the right are the outcomes that are possible when a couple has three children. Refer to that list, and find the probability of each event. a. Among three children, there are exactly 2 boys. b. Among three children, there are exactly 3 boys. c. Among three children, there is exactly 1 boy.

The probabilities are 3/8, 1/8 and 3/8 respectively

Step-by-step explanation:

The sample space for the provided case can be written as:

S= {(bbb, bbg, bgb, bgg, gbb, gbg, ggb, ggg)}

Here, boy child is denoted by "b" and girl child by "g".

Total number of outcomes are 8.

Number of outcomes that show exactly boys = 3.

Number of outcomes that show exactly 3 boys = 1

Number of outcomes that show exactly 1 boy = 3.

Thus, the required probabilities can be calculated as:

(a)

(b)

(c)

Thus, the required probabilities are 3/8, 1/8 and 3/8 respectively.

1. 3. can also be expressed as (22/7)

2. -4.5

3. 3.6

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c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.