The width of a rectangle is 2m less than the length. The area is 48m squared. Find the dimensions.

Length of the rectangle is 8m and width is 6m

Step-by-step explanation:

48 = x (x - 2)

48 = x² - 2x

x² - 2x - 48 = 0

x² - 8x + 6x - 48 = 0

x(x - 8) + 6(x - 8) = 0

(x + 6)(x - 8) = 0

x = -6, 8 (neglecting the negative value)

∴ Length of the rectangle = 8m

∴ Width of the rectangle = 8 - 2 = 6m

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d

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116