WUIZ
9. The length of a rectangle is 4 inches greater than the width. The perimeter of the
rectangle is 24 inches. What are the dimensions of the rectangle?
O
A length = 12 in.; width = 8 in.
B length = 8 in.; width = 4 in
c length = 8 in.; width – 6 in.
D length = 6 in.; width = 2 in.

B length = 8 in.; width = 4 in

Step-by-step explanation:

Given

the length L = w + 4

Perimeter = 24 inches

Perimeter of a rectangle

= 2(L + W)

We now have two equations.

Equation 1: L = w + 4

Equation 2: P = 2(L + W)

Substitute L as w + 4 into equation 1. And 24 for p

Therefore

24 = 2(w + 4 + w)

24 = 2(2w + 4)

Distribute 2 into (2w + 4)

We have

24 = 2 x 2w + 2 x 4

24 = 4w + 8

Subtract 8 from both sides

24 - 8 = 4w + 8 - 8

16 = 4w

Divide both sides by 4

16/4 = 4w/4

4 = w

w = 4 inches

Now substitute 4 for w into either of the equations to get

L.

Using equation 1 , we have

L = w + 4

L = 4 + 4

L = 8 inches

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation:

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step-by-step explanation: