What was the value of x and y for the following equations? Equation 1: 2/3 (x-6) = 6 Equation 2: 2/3y - 6 = 6 x = 15, y = 15 x = 18, y = 15 x = 18, y = 18 x = 15, y = 18

The value of x is 15 and value of y is 18

Solution:

Given equations are:

From first equation,

From second equation,

Thus value of x is 15 and value of y is 18

goog may have it for you

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: