A person’s blood pressure is monitored by taking 3 readings daily. The probability distribution of his reading had a mean of 132 and a standard deviation of 5. Each observation behaves as a random sample. Find the mean of the sampling distribution of the sample mean for the three observations each day.

The mean of the sampling distribution of the sample mean for the three observations each day is 132.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 132

Standard Deviation, σ = 5

Each observation behaves as a random sample.

a) Mean of the sampling distribution

b) Standard deviation of the sampling distribution

Sample size,n = 3

Thus, the mean of the sampling distribution of the sample mean for the three observations each day is 132.

good luck on your studies! : )

david edward.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)