A graph of the function g(x) = x^4-8x³+x²+42x has zeros at -2, 0, 3 and 7. What are the signs of the values between 0 and 3? Show algebraically how you know.

The answer to your question is Positive

Step-by-step explanation:

Function

                  g(x) = x⁴ - 8x³ + x² + 42x

To know if the function is positive or negative in the interval (0, 3), look for two numbers between this interval and evaluate the function.

The numbers I chose were 1 and 2

-  g(1) = (1)⁴ - 8(1)³ + (1)² + 42(1)

         = 1 - 8 - 1 + 42

        = + 36    positive

-  g(2) = (2)⁴ - 8(2)³ + (2)² + 42(2)

          = 16 - 64 + 4 + 84

          = + 40

Conclusion

The function is positive in the interval (0, 3)  

answer:   b

step-by-step explanation:

x2 = 16

x can not be a negative number because 16 is positive

the only answer would be positive 8