The equation r(t)= (3t+9)i+(sqrt(2)t)j+(t^2)k is the position of a particle in space at time t. Find the angle between the velocity and acceleration vectors at time t=0
What is the angle? radians

, for all

Step-by-step explanation:

The velocity vector is found by deriving the position vector depending on the time:

In turn, acceleration vector is found by deriving the velocity vector depending on time:

Velocity and acceleration vectors at are:

Norms of both vectors are, respectively:

The angle between both vectors is determined by using the following characteristic of a Dot Product:

Given that cosine has a periodicity of . There is a family of solutions with the form:

, for all

d (5 x (-20)) * (100 x (0.7))

step-by-step explanation:

5÷1/100 * -.7 *-20

copy dot flip

5*100 * -.7 *-20

rearrange

5*-20   * 100 *-.7

-100   *-70

7000

answer: the answer is 5/22

step-by-step explanation: if you subtract 17 from 22 the answer is 5 therefore the remainder of students are female