An open box will be made from a rectangular piece of cardboard that is 8 in. by 10 in. The box will be cut on the dashed red lines, removing the corners, and then folded up on the dotted lines. What is the MAXIMUM possible volume for the box?A) 1.5 in3B) 5.8 in3C) 52 in3D) 64 in3

C) 52 in^3

Step-by-step explanation:

The first is to determine the formula of the volume of the box, which would be the following:

 V = height * length * width

Knowing that we have a rectangular piece we will determine the maximum volume, we will double a distance x (which will be the height) in the width and length of the piece, therefore as it is on both sides, the length and width are defined from the Following way:

length = 10 - 2 * x

width = 8 - 2 * x

height = x

Now we calculate the volume:

V = x * (10-2 * x) * (8-2 * x)

To determine the maximum volume we will give values to x in order to see how it behaves:

Let x = 2.5

V = (5) * (3) * (2.5) = 37.5

Let x = 2

V = (6) * (4) * (2) = 48

Let x = 1.5

V = (7) * (5) * (1.5) = 52.5

Let x = 1

V = (8) * (6) * (1) = 48

Let x = 0.5

V = (9) * (7) * (0.5) = 31.5

It can be seen that the greatest volume is obtained when the height is equal to 1.5 and its volume is 52.5 in ^ 3

the answer is 489

step-by-step explanation:

- both graphs increase on their domain.

- the graphs of both functions have the same x-intercept.

- neither graph has a y-intercept.