Why does (x-2)^2+9=0 have no real solutions?

see explanation

Step-by-step explanation:

Given

(x - 2)² + 9 = 0 ( subtract 9 from both sides )

(x - 2)² = - 9  ( take the square root of both sides )

x - 2 = ±

yields no real solutions

There is no real number when multiplied by itself gives - 9

In fact the solutions to are said to be imaginary, that is ± 3i

where i =

If interested investigate further.

9 x 8 divided by (5-3)=36

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17