Find the vertex and axis of symmetry for f(x)=2x^2-1

Solution:

Given is:

We have to find the vertex and axis of symmetry

The general equation is given as:

Comparing with given equation,

a = 2

b = 0

c = -1

The axis of symmetry is given as:

Thus axis of symmetry is 0

The x coordinate of the vertex is the same

x coordinate of the vertex = 0

h = 0

The y coordinate of the vertex is:

k = f(h)

k = f(0)

Thus, y coordinate of the vertex is -1

Therefore, vertex is (0, -1)