How would you "remove the discontinuity" of f ? In other words, how would you define f(3) in order to make f continuous at 3? f(x) = x2 − 2x − 3 x − 3

Since it's a removable discontinuity, we will remove the discontinuity by creating a new function defined by x=3;

So we have;

F(x) = {[x² - 2x - 3]/(x-3); x ≠ 3

         {4, x = 3

Step-by-step explanation:

I have attached my explanation as the system here is not allowing me to save my answer.

d is correct

step-by-step explanation:

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b