Find the zeros of each function

f(x)=(x-3)(x+5)

The zeros of this function are 3 and -5.

Step-by-step explanation:

One note: The question says "Find the zeros of EACH function", but there seems to be only one function in the question. I hope I answered it well.

To complete the function provided, you need to get both terms inside both parenthesis to equal zero. So, if its (x-3)(x+5), the X's need to equal the opposite of the number that is being added or subtracted.

For the first parenthesis, (x-3), the number is -3, so the zero of that side is positive 3. (3-3 = 0)

For the second parenthesis, (x+5), the number is positive 5, so the zero of that side is -5. (-5+5 = 0)

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15