I really need help but I keep getting my question taken down. Please help.

2. Draw a right triangle with side lengths of 3, 4, and 5 units (cm or inches – your choice). Make sure to label all parts including side lengths, vertices, and the right angle. You may insert an actual picture of your drawing below or upload the picture in the Unit 2 TGA submission area.

Explanation:

In a right triangle the longest side is the hypotenuse. In this case the length is 5 units.

The hypotenuse is opposite to the right angle.

You must draw a small square inside the right angle. In the figure the right angle is labeled C.

The other two sides are the legs: in this case their lengths are 3units and 4 units.

The side with the shortest length is opposite to the smallest angle; the side with the intermediate length is opposite to the angle with the intermediate measure.

The vertices are marked with capital letters. I used A, B, and C.

With this explanation you can understand the figure attached and build one on your own.

15 batches are the most you can make

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15