Jon’s picture frame is 6 inches high by 5 inches wide. He wants to know what other size frames he can use if he enlarges the photo by using the same relative proportions for length and width.

A picture frame is 6 inches high by 5 inches wide.

How can Jon find the sizes of other frames?
Jon can plot the ratio of 5 to 6 on a graph (5, 6), then move up 6 and left 5 to find the next frame size, and then keep the same rate to find other points.
Jon can plot the ratio of 5 to 6 on a graph (5, 6), then move up 6 and right 5 to find the next frame size, and then keep the same rate to find other points.
Jon can plot the ratio of 6 to 5 on a graph (6, 5), then move right 6 and down 5 to find the next frame size, and then keep the same rate to find other points.
Jon can plot the ratio of 6 to 5 on a graph (6, 5), then move right 5 and up 6 to find the next frame size, and then keep the same rate to find other points.

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

b and c

step-by-step explanation:

answer: its the third option.

step-by-step explanation:

i just took the test.