The time, in number of days, until maturity of a certain variety of tomato plant is Normally distributed, with mean μ and standard deviation s = 2.4. You select a simple random sample of four plants of this variety and measure the time until maturity. The sample yields ¯x = 65. You read on the package of seeds that these tomatoes reach maturity, on average, in 61 days. You want to test to see if your seeds are reaching maturity later than expected, which might indicate that your package of seeds is too old.
The appropriate hypotheses are:

a) H0 : μ = 61 , Hα : μ > 61 .
b) H0 : μ = 65 , Hα : μ < 65 .
c) H0 : μ = 61 , Hα : μ < 61 .
d) H0 : μ = 65 , Hα : μ > 65 .

Option a)  H0 : μ = 61 , Hα : μ > 61 .

Step-by-step explanation:

We are given that the time, in number of days, until maturity of a certain variety of tomato plant is Normally distributed, with mean μ and standard deviation s = 2.4.

You select a simple random sample of four plants of this variety and measure the time until maturity. The sample yields x bar = 65.

You read on the package of seeds that these tomatoes reach maturity, on average, in 61 days.

Now, since we know about;

sample size, n = 4

sample standard deviation, s = 2.4

sample, x bar = 65

The only line which represent information about the population mean is reading on the package of seeds that these tomatoes reach maturity, on average, in 61 days.

This shows that population mean , = 61 and in null and alternate hypothesis only population mean is tested.

So, Null Hypothesis, : = 61

Alternate Hypothesis, : > 61 { we are asked for later than expected}

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.

if y=4x then you will substitute 4x in for y in the second equation.

8x + 4x = 18 combine like terms

12x = 18 divide by 12 on both sides

x = 18/12 or 3/2

now replace x in the first equation with 3/2 to get

y = 4 3/2

y = 6

the answer is a

(3/2,6)

hope that .

brainliest is always apprectiated