Members of a hospital advisory committee will be selected from 5 doctors and 4 nurses. The committee must have 2 doctors and 2 nurses.

How many possible combinations of doctors and nurses could be chosen for the committee?

16 possible ways

Step-by-step explanation:

Using the formular Cp,k= p!/I! (P-k)!

Where k= number of selected committee members

P= available number that can sit in the committee

For doctors,there are 5 doctors

C= 5!/2!(3)!= 120/12 = 10ways

For nurses,there are 4

C= 4!/2!(2)! = 24/4 =6ways

Total possible ways=10 + 6 = 16 ways

60

Step-by-step explanation:

(2 out of 5 doctors) * (2 out of 4 nurses)

i need the options

step-by-step explanation:

they can both be solutions depends on the equation

step-by-step explanation:

what is the equation? ?