Carol can complete her neighborhood jog in 10 minutes. It takes 30 minutes to cover the same distance when she walks. If her jogging rate is 4 mph fater than her walking rate, find the speed at which she jogs.

6mph

Step-by-step explanation:

In this question, we are asked to calculate the speed at which Carol jogs, given that she has a particular speed when she jogs greater than when she walks.

Firstly, we should understand that she is taking the same distance, whether she jogs or walks.

Now, let’s say her jogging rate is x mph, this means that her walking rate would be (x - 4)mph. This is because her jogging rate is 4mph faster than her walking rate.

The total distance covered when jogging is thus 10/60 * x, while her total distance covered when walking would be 30/60 * (x-4)[we convert the time to hours]

We equate both since they are same distance:

x/6 = (x -4)/2

2x = 6(x - 4)

2x = 6x - 24

4x = 24

x = 6mph

i can't read the graph

step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240