Line a is formed by using the points -1,6 and 3,-2 Line B is formed by using the point -3,0 and 5,4.What linear equations can be used to represent each line

y  =  -x  + 5

y  =  x/2  + 3/2

Step-by-step explanation:

First we calculate the slope as difference between coordinates

a) P₁ ( -1 , 6 )   P₂  ( 3 , 2 )

m =  Δy/Δx      ⇒  m  =  (  y₂ - y₁ ) / ( x₂ - x₁ )  ⇒  m = (2 -6 ) / (3 -(-1))

m =  -4 /4  

m = -1

Now we have:

y - y₁  = m ( x - x₁ )    ⇒  y  -  6  = (-1) ( x - (-1))

y  -  6  =  -1 * ( x + 1 )   ⇒  y  -  6  =  - x - 1

y  =  -x  + 5

In the second case

Q₁  ( -3 , 0 )  Q₂  ( 5  , 4 )

Again we calculate the slope

m  =  Δy / Δx    ⇒  m  =  ( 4 - 0 ) / ( 5 - (-3))    ⇒  m =  4 / 8   ⇒ m = 1/2

m  = 1/2  or  x = 0,5

And

y - y₁  = 1/2 ( x - x₁ )   ⇒  y  -  y₁  = 1/2 ( x - (-3))   ⇒   y  - 0 = 1/2 * x + 3/2

y  =  x/2  + 3/2

p> q if you calculate p is100 q is 79

70,000 + 6,000 + 800 + 30

step-by-step explanation: