You take a trip by air that involves three independent flights. If there is an 67% chance each specific leg of the trip is on time, what is the probability all three flights arrive on time

The required probability is 0.301.

Step-by-step explanation:

Since we have given that

Probability that each specific leg of the trip is on time = 67%

Number of independent flights = 3

We will use "Binomial distribution" to find the probability that all three flights arrive on time.

Here p = 0.67

q = 1-0.67 = 0.33

So, the probability that all three flights arrive on time is given by

Hence, the required probability is 0.301.

(4,5

look up a corrdinate plane and do what the thingy says and boom

-6 is the correct option from the above given options