A scatter plot of data comparing the number of years since holbrrok high school introduced a math club and the number of students participating contains the ordered pairs (3, 19) and (8, 42). which is the slope intercept form of an equation for the line of fit containg those poitns

Therefore, the equation of the line containing those points is;

y = (23/5)x + 26/5

or

y = 4.6x + 5.2

Step-by-step explanation:

The standard slope-intercept form of a straight line equation is;

y = mx + c

where m = slope

c = intercept

the slope can be derived from;

m = ∆y/∆x

Given the (x,y) points

(3,19) and (8,42)

m = (42-19)/(8-3)

m = 23/5 or 4.6

To determine the intercept, using point 1 (3,19) and substituting the slope.

y = mx +c

19 = (23/5)3 + c

c = 19 - 69/5

c = 26/5

Therefore, the equation of the line containing those points is;

y = (23/5)x + 26/5

or

y = 4.6x + 5.2

I’m going to cry

Step-by-step explanation:

TOO HARD.

step-by-step explanation:

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4