What is a difference of squares with a factor of (3x + 7) ?

9x² - 49

Step-by-step explanation:

A difference of squares factors in general as

a² - b² = (a + b)(a - b)

Given (3x + 7) with a = 3x and b = 7

Then the other factor is (3x - 7)

(3x + 7)(3x - 7)

= (3x)² - 7²

= 9x² - 49

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x