Thickness measurements of a coating process are made to the nearest hundredth of a millimeter. The thickness measurements are uniformly distributed with values 0.14, 0.15, 0.16, 0.17, 0.18. Determine the mean and variance of the coating thickness for this process. Round your answers to four decimal places (e. g. 98.7654).

We can calculate the sample variance with the following formula:

And replacing we got:

And the deviation is given by this:

If we want to find the population deviation we just need to use this formula:

And replacing we got:

And the population deviation would be:

Step-by-step explanation:

For this case we have the following values:

0.14, 0.15, 0.16, 0.17, 0.18.

We can calculate the mean with the following formula:

And replacing we got:

We can calculate the sample variance with the following formula:

And replacing we got:

And the deviation is given by this:

If we want to find the population deviation we just need to use this formula:

And replacing we got:

And the population deviation would be:

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.