2(6x – 10) + 10 = 5x – 13

Hey there!

2(6x - 10) + 10 = 5x - 13

2(6x) + 2(-10) + 10 = 5x - 13

12x - 20 + 10 = 5x - 13

12x - 10 = 5x - 13

SUBTRACT 5x to BOTH SIDES

12x - 10 - 5x = 5x - 13 - 5x

SIMPLIFY IT!

NEW EQUATION: 7x - 10 = -13

ADD -10 to BOTH SIDES

7x - 10 + 10 = -10 + 13

CANCEL out: -10 + 10 because it gives you 0

KEEP: -10 + 13 because it help solve for the x-value

NEW EQUATION: 7x = -10 + 13

SIMPLIFY IT!

7x = -3

DIVIDE 7 to BOTH SIDES

7x/7 = -3/7

CANCEL out: 7/7 because it gives you 1

KEEP: -3/7 because it help solve for the x-value

NEW EQUATION: x = -3/7

SIMPLIFY IT!

x = -3/7

Therefore, your answer is: x = -3/7

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204