Mathematics, 07.03.2020 04:51 longboard5967
An oil storage tank ruptures at time t = 0 t=0 and oil leaks from the tank at a rate of r ( t ) = 75 e − 0.04 t(t)=75e-0.04to liters per minute. How much oil leaks out during the first hour
Answers: 2
![r(t) = 75 e^{-0.04t}\\\text{Integrating both sides}\\\\\displaystyle\int^{60}_0 = \int^{60}_0 75 e^{-0.04t}dt\\\\=\bigg[\dfrac{75 e^{-0.04t}}{-0.04}\bigg]^{60}_0\\\\=-1875\big[e^{-0.04(60)}-e^{0}\big]\\=-1875(0.0907-1)\\=1704.90\\\approx 1705](/tpl/images/0537/7807/d372f.png)
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An oil storage tank ruptures at time t = 0 t=0 and oil leaks from the tank at a rate of r ( t ) = 75...
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