Scores on a standardized test are approximately normally distributed with a mean of 480 and a standard deviation of 90. A student has a score of 600. What percentile is the student's score closest to

the student's score closest to 91 percentile.

Step-by-step explanation:

Since the scores on the standardized test are approximately normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = test scores.

µ = mean score

σ = standard deviation

From the information given,

µ = 480

σ = 90

If a student has a score of 600, then x = 600

For x = 600,

z = (600 - 480)/90 = 1.33

Looking at the normal distribution table, the probability corresponding to the z score is 0.91

the student's score closest to 91 percentile.

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!