Use the coordinates of the labeled point to find a point-slope equation of the line (4, -2) a. Y-2=-2(x+3) b. Y-2=2(x+4) c. Y+2=-2(x-4) d. Y+2=2(x-4)

d. Y+2=2(x-4)

Step-by-step explanation:

we have one point

(4, -2)

and 4 equations

a. Y-2=-2(x+3)

b. Y-2=2(x+4)

c. Y+2=-2(x-4)

d. Y+2=2(x-4)

we have to replace the x with 4 and the y with -2

and in the equation that equality is fulfilled is a correct option

a.

Y-2=-2(x+3)

(-2)-2=-2((4)+3)

-4=-2(7)

-4 = -14

Wrong

b.

Y-2=2(x+4)

-2-2=2((4)+4)

-4=2(8)

-4 = 16

Wrong

c.

Y+2=-2(x-4)

(-2)+2=-2((4)-4)

-4 = -2(0)

-4 = 0

Wrong

d.

Y+2=2(x-4)

(-2)+2 = 2((4)-4)

0 = 2(0)

0 = 0

Correct

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: