The graph of a system of equations shows the solution to be at (-6,2) which two of the following equations could make up this system? THERE ARE 2.

A. 2x-3y=-6
B. 4x-y=26
C. 3x+2y=-14
D. X-y=-2
E. X+y=-4

C and E

Step-by-step explanation:

Substitute (- 6, 2) into the left side of each equation and if equal to the right side then that is a possible equation

A

2(- 6) - 3(2) = - 12 - 6 = - 18 ≠ - 6

B

4(- 6) - 2 = - 24 - 2 = - 26 ≠ 26

C

3(- 6) + 2(2) = - 18 + 4 = - 14 ← this is correct

D

- 6 - 2 = - 8 ≠ - 2

E

- 6 + 2 = - 4 ← This is correct

Thus the 2 possible equations are C and E

C & E

Step-by-step explanation:

3(-6) + 2(2) = -14

-6 + 2 = -4

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363

900 degrees

step-by-step explanation: