ABC is a triangle. The sides AB and AC are produced to D and E respectively such that angle DBC=132° and angle EBC=96°. Show that ABC is isosceles.

Proof:

Ange EBC is 96° so the angle CBA is

180 - 96 ( angles on a straight line )

So angle CBA is 84°

I think ANGLE DBC SHOULD BE CORRECTED TO ANGLE DCB

And angle DCB is 132° so the angle BCA is equal to 48°

So to find BAC angle

48 + 84 + BAC = 180 ( interior angles of a triangle)

so angle BAC is 180 - 132

Which is again 48°

So the angles BAC = BCA

Hence the sides BC = BA

so ABC triangle is isosceles ( two angles and the two sides are equal)

it would open into a square depending on the type of envelope i’m not sure about the second part

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

tap for more

m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0