Find the equation of the parabola in the focus at (2, -3), the directrix x+5=0

Step-by-step explanation:

We want to find the equation of the parabola in the focus at (2, -3), the directrix x+5=0.

We know that the vertex is the midpoint of the focus and the directrix(where it intersect the axis of symmetry)

The midpoint of x=-5 and x=2 is x=-1.5

The y-coordinate of the vertex is still -3.

So the vertex is (-1.5,-3)

This is a horizontal parabola that opens to the right.

The equation is of the form

The vertex is (h,k)=(-1.5,-3) and p=|2--1.5|=3.5

We substitute to get:

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.