If the daily cost per unit of producing a product by the Ace Company is 20 + 0.2x dollars, and if the price on the competitive market is $70, what is the maximum daily profit the Ace Company can expect on this product?

I got $125. If someone could please explain what I did wrong I'd appreciate it.

$3125

Step-by-step explanation:

The profit is the revenue minus the cost.

p = (70) x − (20 + 0.2x) x

p = 70x − 20x − 0.2x²

p = -0.2x² + 50x

The maximum profit is at the vertex of the parabola.

x = -b / (2a)

x = -50 / (2 × -0.2)

x = 125

The maximum profit is:

p = -0.2(125)² + 50(125)

p = 3125

It seems you correctly found the number of units needed to maximize the profit, but you forgot to plug it back into the equation to get the profit.

$3125

Step-by-step explanation:

Cost = x(20 + 0.2x)

= 20x + 0.2x²

MC = 20 + 0.4x

MR = MC

70 = 20 + 0.4x

x = 125

Cost = 20 + 0.2x = 45

Profit per unit = 70 - 45 = 25

Total profit = 125×25 = $3125

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )