The gold bar has a trapezium cross section area (6+12) x 5/2. Gold has a density of 19.3 grams per cm^3.Work put the mass of the gold bar. Put your answer in kilograms

Step-by-step explanation:

The volume of the gold bar= area of trapezium x length of gold bar

We know the length of the gold bar is 16 cm

Area trapezium formula: 1/2 (a+b)*h

So for the area of the trapezium: (6 + 12)*5 /2 which makes 45 cm^2

Volume of gold bar= 45cm^2 x 16 cm which makes 720^3 (links to the volume of gold bar formula)

We also know that the gold has a density of 19.3 g/cm^3

We know that the formula for density is: Density=mass/volume

Rearrange the formula for mass: mass=Density*Volume

Substitute the numbers: 720^3 g*19.3 g = 13986 g

Convert g into kg which you need to divide by 1000

13986/1000=13.986 KG

Hence, the mass of the gold bar is 13.986 KG or 13.99 KG (2 d.p)

I do hope this helps you out :)

Have a nice day!

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

a .4y4

hope this !