When making a long distance call from a certain pay phone, the first three minutes of a call cost $2.10. After that, each additional minute or portion of a minute of that call cost $0.45. Use an inequality to find the number of minutes one can call long distance for $6.15.

the number of minutes of long distance call that one can make is lesser than or equal to 12 minutes.

Step-by-step explanation:

Let x represent the number of minutes of long distance call that one makes.

The first three minutes of a call cost $2.10. After that, each additional minute or portion of a minute of that call cost $0.45. This means that if x minutes of long distance call is made, the total cost would be

2.10 + 0.45(x - 3)

Therefore, the inequality to find the number of minutes one can call long distance for $6.15 is expressed as

2.10 + 0.45(x - 3) ≤ 6.15

2.10 + 0.45x - 1.35 ≤ 6.15

0.75 + 0.45x ≤ 6.15

0.45x ≤ 6.15 - 0.75

0.45x ≤ 5.4

x ≤ 5.4/0.45

x ≤ 12

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

f(x)=2/3x+4/3 is the answer because is whose power in the senate is equal to the power of the speaker of the house?

step-by-step explanation: