At the end of a race a runner decelerates from a velocity of 8.00 m/s at a rate of 0.400 m/s2.
(a) How far does she travel in the next 15.0 s

75 m

Step-by-step explanation:

The formula to apply here is;

d(t)= v₀t + at²/2

where

d=distance covered in time t

v₀=initial velocity in m/s

t=time taken in seconds

a=deceleration

Given that

v₀=8.00 m/s

t=15 sec

a= -0.400 m/s²

d(15)= 8.00 *15 + (-0.400*15²)/2

d(15)=120 + -90/2

d(15)= 120-45 =75 m

-232

step-by-step explanation:

x + 4/7

step-by-step explanation:

use cymath