Suppose that m∠MKN = 55°. What is m∠MCN?
!please no absurd answers!

angle M and N are right angles

we can draw a line joining M and N  

so we’d have a triangle MNC AND KMN

both MNC AND KMN BECOME ISOSCELES TRIANGLES

so since we have 55 degrees for angle MKN. We have to find the other 2

180-55=125

now divide by 2 to get 62.5 for each of the remaining sides of triangle KMN

now to find the sides of triangle MNC

90-62.5= 27.5

27.5*2= 55

180-55=125=angle C

(sorry, it’s complex)

Taking into account that in the point of contact, the tangent to a circle is perpendicular to the radius, we have angles KMC = angle KNC = 90⁰.

In a 4-sides polygon (KMCN), the sum of all angles is 360⁰:

55+90+MCN+90=360

MCN=180-55=125⁰

MCN=125⁰

8

step-by-step explanation:

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %