Two horses start a race at the same time . Horse A gallops at a steady rate of 32 feet per second and Horse B gallops at a steady rate of 28 per second. After 5seconds , how much farther will horse A have traveled

Assuming your question is how much farther has Horse A traveled than Horse B.

So after 5 seconds, Horse A already traveled 160 feet.

While Horse B, after 5 seconds traveled 140 feet.

So the difference is 20 feet.

horse A travelled 20 feet more than horse B

Step-by-step explanation:

The two horses start the race at the same time.

Distance = speed × time

Horse A gallops at a steady rate of 32 feet per second. This means that the distance that horse A covers in 5 seconds would be

32 × 5 = 160 feet.

Horse B gallops at a steady rate of 28 per second. This means that the distance that horse B covers in 5 seconds would be

28 × 5 = 140 feet

The difference in distance covered by both horses is

160 - 140 = 20 feet

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

the first one, all those points on the line just make a strait line.