I need some help with this calculus 1 question.

(a) f'(1)=-4

(b) y+4x-4=0

Step-by-step explanation:

Tangent Line of a Function

Given f(x) a real differentiable function in x=a, the slope of the tangent line of the function in x=a is given by f'(x=a). Where f' is the first derivative of f.

We are given

The derivative is

(a) The slope of the tangent line at (1,0) is

(b) The equation of the tangent line can be found with the general formula of the line:

Where m is the slope and the point (xo,yo) belongs to the line. We have m=-4, xo=1, yo=0, thus

Or, equivalently

hope this !

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step-by-step explanation:

duck you