To snails are 189 cm apart. They crawl towards each other at rates that differ by 1 cm a minute. After 27 minutes they meet. How fast is each snail crawling?

Speed of snail 1 = 3.795 cm/minute

Speed of snail 2 = 4.795 cm/minute

Solution:

Given that,

Total distance = 189 cm

They crawl towards each other at rates that differ by 1 cm a minute

Let the speed of snail 1 be "x"

Let the speed of snail 2 be "x + 1"

Total time = 22 minutes

Since the snails are moving towards each other,

Speed = x + x + 1 = 2x + 1

How fast is each snail crawling?

Thus,

Speed of snail 1 = 3.795 cm/minute

Speed of snail 2 = 3.795 + 1 = 4.795 cm/minute

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step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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