G Create a new Die object. (Refer to Die. html for documentation.)Create a loop that will iterate at least 100 times. In the loop body:Roll the die. (Don't create a new object, just roll it again.)Based on the result of the roll, increment the corresponding cell of your array.

Step-by-step explanation:

import java.util.Random;

class Die{

private int sides;

public Die(){

sides = 6;

}

public Die(int s){

sides = s;

}

public int Roll(){

Random r = new Random();

return r.nextInt(6)+1;

}

}

class DieRoll{

public static void main(String[] args) {

Die die = new Die();

int arr[] = new int[6];

for(int i=0; i<6; i++)

arr[i] = 0;

for(int i=0; i<100; i++){

int r = die.Roll();

arr[r-1]++;

}

for(int i=0; i<6; i++)

System.out.println((i+1)+" was rolled "+arr[i]+" times.");

}

}

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

idk

step-by-step explanation:

use that smart brain