Tell A: 3 C: 3.0 Hints: 0,0 Try 1 - CORRECT! 14.29 points added to your score # tries: 1 D. (Review) You put 1 kg of ice at 0°C together with 1 kg of water at 50°C. What is the final temperature?

-14.88° C

Step-by-step explanation:

specific heat capacity of water, c = 4200 J/KgK

latent heat of fusion of ice, l = 3.35 × 10⁵Jkg⁻¹

Heat loss by water = heat gain by ice

heat gain by ice = ml + mc ( T - 0°C) where m is the mass of ice

(1 kg × 3.35 × 10⁵Jkg⁻¹) + 1 kg ×  4200 J/KgK ( T - 0°C) where T, temperature is the final temperature of the mixture

3.35 × 10⁵ + 4200 T

heat loss by water = mc ( 50° C - T) = 1kg × 4200 J/KgK ( 50° C - T) = 210000 - 4200 T

heat gain by ice = heat loss by water

3.35 × 10⁵ + 4200 T = 210000 - 4200 T

4200 T + 4200 T = 210000 - 335000

8400 T = -125000

T = -125000 / 8400 = -14.88° C

i think it is 70

step-by-step explanation: