In the following problem, let A = 1 7 −1 1 1 1 1 −1 0 , B = 1 −1 0 1 1 1 1 7 −1 . Find an elementary matrix E that satisfies the given equation. EA = B

Elementary matrix is;

E = {0 0 1}

{0 1 0}

{1 0 0}

Step-by-step explanation:

Since we are to find EA = B,thus E = B/A

So in matrix laws; B/A = B(A^(-1))

Now, (A^(-1)) =

(1/10){ 1 1 8 }

(1/10){ 1 1 -2 }

(1/10){ -2 8 -6 }

Where 1/10 is 1/determinant of A

B matrix is;

{ 1 -1 0 }

{ 1 1 1 }

{ 1 7 -1 }

So; B(A^(-1)) gives;

0 0 1

0 1 0

1 0 0

true

explanation:

no he doesnt because "-16' is negatiive

step-by-step explanation: