- To approach the runway, a small plane must begin a 6° descent starting from a height of 1297 feet above the
ground. To the nearest tenth of a mile, how many miles from the runway is the airplane at the start of this
approach?

Step-by-step explanation:

Use the equation: sin(Theta)=opposite/ hypotenuse

X shows the how far from approach

so sin(26)=1297/x

rearrange to make: X=1125/sin(26

so 1125/sin(26)= 2,566.3 miles

Therefore, it will be 2,566.3 miles from approach

hope this helps :)

Have a nice day

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.