Find all complex solutions of x^2-5x+7=0

x1=5/2+i

x2=5/2-i

Step-by-step explanation:

x^2-5x+7=0

a=1, b=-5, c=7

x1=(-b+sqrt(b^2-4ac))/2a

x1=(-(-5)+sqrt(5^2 - 4*1*7))/2

x1=(5+sqrt(25-28))/2

x1=(5+sqrt(-4))/2

x1=(5+sqrt(4i^2))/2

x1=(5+2i)/2

x1=5/2+i

x2=(-b-sqrt(b^2-4ac))/2a

x2=(5-2i)/2

x2=5/2-iw

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

can you put the picture up?

step-by-step explanation: