Mathematics, 10.03.2020 04:31 briceevans32

The length of a new rectangular playing field is 55 yards longer than tripletriple the width. If the perimeter of the rectangular playing field is 426426 yards, what are its dimensions?

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Answer from: valerieaj113

The length of the rectangle is 159923.5 and the width of 53289.5

Step-by-step explanation:

We will make 2 equations one that is the perimeter and another that is the length with respect to the width

b = w*3+55

2b + 2 w = 426426

we will replace b with (w * 3 + 55) in the second equation

2b + 2 w = 426426

2(w*3+55) + 2w = 426426

we clear w to find its value

6w + 110 + 2w = 426426

8w = 426426 - 110

8w = 426316

w = 426316/8

w = 53289.5

Now that we have the value of w we replace it in the first equation and solve to find b

b = w*3 + 55

b = 53289.5*3 + 55

b = 159868.5 + 55

b = 159923.5

Answer from: annamcveigh50

length = 173.5 yards

Width = 39.5 yards

Step-by-step explanation:

Let L represent the length of the rectangular garden.

Let W represent the width of the rectangular garden.

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

If the perimeter of the rectangular playing field is 426 yards. This means that

2(L + W) = 426

Dividing through by 2, it becomes

L + W = 213 - - - - - - - - - - - -1

The length of a new rectangular playing field is 55 yards longer than triple the width. This means that

L = 55 + 3W

Substituting L = 55 + 3W into equation 1, it becomes

55 + 3W + W = 213

4W + 55 = 213

4W = 213 - 55

4W = 158

W = 158/4

W = 39.5

L = 55 + 3W = 55 + 3 × 39.5

L = 55 + 118.5

L = 173.5

Answer from: Quest

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function $y=f(x)$ the average rate of change from point $a(a,f(a))$ to point $b(b,f(b))$ can be calculated as

$\text{average rate of change}=\dfrac{f(b)-f(a)}{b-a}.$

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,

$\text{average rate of change}=\dfrac{2-8}{10-2}=\dfrac{-6}{8}=-\dfrac{3}{4}.$

The graph below shows the number of houses sold over x days. what is the average rate of change from

Answer from: Quest

answer: 75°

step-by-step explanation:

∠esk is the supplement of ∠edk, so is 100°. ∠esd = 1/2·arc ed, so is 25°.

since ∠esk = ∠esd + ∠dsk

you have 100° = 25° + ∠dsk . .

fill in known values 75° = ∠dsk . . . . .

subtract 25°

step-by-step explanation:

Basic circle problem given: measure of arc ed = 50°, m∠edk = 80° find: ∠dsk

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