A boat filled can carry 6 smart cars and 7 Toyota's or 8 smart cars and 4 Toyota's. If the ferry boat were to only carry toyotas what is the maximum number of toyotas aboard the ferry

16

Step-by-step explanation:

Let S is smart car and T is Toyota car

Case 1: 6 smart cars and 7 Toyota's = 6S + 7T

Case 2: 8 smart cars and 4 Toyota's

When 2 smart cars increase = 3 Toyota's cars descrease

So the ratio between them is:

2S = 3T

<=> S= 3/2T

so the maximum number of toyotas aboard the ferry

6*3/2T + 7T = 16 T

it's d.

step-by-step explanation:

because: -1(4x + 1y) +2 (1x-3y) distribute each number into the parenthesis.

then you would get: -4x - 1y + 2x -6y combine like terms

and get: 2x -7y

hope my answer has you if not then i'm sorry.